Question

A competitive cliff-diver jumps from a height of 75 feet. Find the number of feet the diver is above the ocean in 2 seconds. Evaluate for t=2
by using the formula 75−16t2
, where t
is time in seconds.(1 point)

Answer 1

To find the number of feet the cliff-diver is above the ocean at \( t = 2 \) seconds, we can use the formula given:

\[
h(t) = 75 - 16t^2
\]

Substituting \( t = 2 \) into the formula:

\[
h(2) = 75 - 16(2^2)
\]

Calculating \( 2^2 \):

\[
2^2 = 4
\]

Now substituting back into the formula:

\[
h(2) = 75 - 16(4)
\]

Calculating \( 16 \times 4 \):

\[
16 \times 4 = 64
\]

Now substituting this value back:

\[
h(2) = 75 - 64
\]

Finally, calculating \( 75 - 64 \):

\[
h(2) = 11
\]

Thus, the diver is **11 feet above the ocean** at \( t = 2 \) seconds.