Asked by Amphee
                The initial pressure for the compounds involved in the reaction shown were determined to be P(Br2(g)) = 0.5417 atm, P(Cl2(g)) = 0.6962 atm, P(BrCl(g)) = 0.3442 atm. Calculate the value of the equilibrium constant (Kp) at 1000 K if the equilibrium pressure of Cl2(g)  was 0.7246 atm. 
Br2(g)+Cl2(g) = 2BrCl(g)
The answer is 0.2000. I having hard time getting this answer. Thanks.
            
        Br2(g)+Cl2(g) = 2BrCl(g)
The answer is 0.2000. I having hard time getting this answer. Thanks.
Answers
                    Answered by
            DrBob222
            
    If you are still having trouble with this, please post again at the top of the page and someone will help. It would help if you posted your work and we can find the error. 
    
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