Question

If the initial pressure of SO3(g) is 4.775 atm, calculate the % of SO3(g) left over after the reaction reaches equilibrium according to the balanced equation. The value of Kp at 1000 K is 24.40. The initial pressure of the reaction products is 0 atm.


2SO3(g) = 2SO2(g)+O2(g)

Unit Conversions
K = C + 273
i have no clue on this problem on how to find percent

Answer 1

There is no need for you to have K=C=273 because you have nothing in Celcius. But 1000k is 24.40 and the pressure is at 0 atm

Ok

Ip-4.775
SO3 grams
1000k is 24.40

Your looking for percent compisition.

So you have to get

S-32.066x1= 32.06/32.06=??
O-16.00x3= 48/32.06=??


Then you get the answer the the nearest whole.
Then you should get a ratio.

Answer 2

can you be clearer a bit, i gont get why you try to find
S-32.066x1= 32.06/32.06=??
O-16.00x3= 48/32.06=??

why is 32.06/32.06, where did that number come from

we don't need to use 4.775 and 24.4 to solve this?

Answer 3

I never used those numbers, and you got the 32.06 because you need to divide each number by the smallest number of moles.

Answer 4

I hope you get it, im getting off.

Answer 5

004200 i need to changed to scientific notation