Asked by _behindyou_
Expand and simplify the expression: -5/7(3x + 1/4y) - 9(x/7 - 1/28y)
(-5/7)(3x/1) + (-5/7)(1/4 ?) + (-9)(x/?) + (-9)(-1/28y)
-15x/7 - 5/28y - 9x/7 + ?/28y
-?/7x + 4/28y
-24/7x + ?/7y
(-5/7)(3x/1) + (-5/7)(1/4 ?) + (-9)(x/?) + (-9)(-1/28y)
-15x/7 - 5/28y - 9x/7 + ?/28y
-?/7x + 4/28y
-24/7x + ?/7y
Answers
There are no human answers yet.
Answered by
GPT-4o mini
Let's work through the expansion and simplification of the expression step by step.
Starting from the original expression:
\[
-\frac{5}{7}(3x + \frac{1}{4}y) - 9\left(\frac{x}{7} - \frac{1}{28}y\right)
\]
We'll expand each term separately.
### Step 1: Expand the first term
\[
-\frac{5}{7}(3x) - \frac{5}{7}\left(\frac{1}{4}y\right)
\]
Calculating these:
1. \(-\frac{5}{7} \cdot 3x = -\frac{15}{7}x\)
2. \(-\frac{5}{7} \cdot \frac{1}{4}y = -\frac{5}{28}y\)
So, we have:
\[
-\frac{15}{7}x - \frac{5}{28}y
\]
### Step 2: Expand the second term
\[
-9\left(\frac{x}{7}\right) - 9\left(-\frac{1}{28}y\right)
\]
Calculating these:
1. \(-9 \cdot \frac{x}{7} = -\frac{9}{7}x\)
2. \(-9 \cdot -\frac{1}{28}y = \frac{9}{28}y\)
So, we have:
\[
-\frac{9}{7}x + \frac{9}{28}y
\]
### Step 3: Combine the results
Now we will combine the results from both expansions:
\[
-\frac{15}{7}x - \frac{5}{28}y - \frac{9}{7}x + \frac{9}{28}y
\]
### Step 4: Combine the \(x\) terms and the \(y\) terms
- For the \(x\) terms:
\[
-\frac{15}{7}x - \frac{9}{7}x = -\left(\frac{15 + 9}{7}\right)x = -\frac{24}{7}x
\]
- For the \(y\) terms:
\[
-\frac{5}{28}y + \frac{9}{28}y = \left(-5 + 9\right)\frac{1}{28}y = \frac{4}{28}y = \frac{1}{7}y
\]
Thus, putting it all together, we have:
\[
-\frac{24}{7}x + \frac{1}{7}y
\]
The final simplified expression is:
\[
-\frac{24}{7}x + \frac{1}{7}y
\]
Starting from the original expression:
\[
-\frac{5}{7}(3x + \frac{1}{4}y) - 9\left(\frac{x}{7} - \frac{1}{28}y\right)
\]
We'll expand each term separately.
### Step 1: Expand the first term
\[
-\frac{5}{7}(3x) - \frac{5}{7}\left(\frac{1}{4}y\right)
\]
Calculating these:
1. \(-\frac{5}{7} \cdot 3x = -\frac{15}{7}x\)
2. \(-\frac{5}{7} \cdot \frac{1}{4}y = -\frac{5}{28}y\)
So, we have:
\[
-\frac{15}{7}x - \frac{5}{28}y
\]
### Step 2: Expand the second term
\[
-9\left(\frac{x}{7}\right) - 9\left(-\frac{1}{28}y\right)
\]
Calculating these:
1. \(-9 \cdot \frac{x}{7} = -\frac{9}{7}x\)
2. \(-9 \cdot -\frac{1}{28}y = \frac{9}{28}y\)
So, we have:
\[
-\frac{9}{7}x + \frac{9}{28}y
\]
### Step 3: Combine the results
Now we will combine the results from both expansions:
\[
-\frac{15}{7}x - \frac{5}{28}y - \frac{9}{7}x + \frac{9}{28}y
\]
### Step 4: Combine the \(x\) terms and the \(y\) terms
- For the \(x\) terms:
\[
-\frac{15}{7}x - \frac{9}{7}x = -\left(\frac{15 + 9}{7}\right)x = -\frac{24}{7}x
\]
- For the \(y\) terms:
\[
-\frac{5}{28}y + \frac{9}{28}y = \left(-5 + 9\right)\frac{1}{28}y = \frac{4}{28}y = \frac{1}{7}y
\]
Thus, putting it all together, we have:
\[
-\frac{24}{7}x + \frac{1}{7}y
\]
The final simplified expression is:
\[
-\frac{24}{7}x + \frac{1}{7}y
\]
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