To determine how many milliliters of oxygen he would consume in one hour with a VO2 max of 64.5 mL O2/kg/min, we first need to know his body weight after losing 21 lbs. However, since we don't have his initial weight, let's denote his final weight after the loss as \( W \) (in kg).
Since 1 pound is approximately equivalent to 0.453592 kg, losing 21 pounds would convert to:
\[ 21 \text{ lbs} \times 0.453592 \text{ kg/lb} \approx 9.525 \text{ kg} \]
Thus, if we denote his original weight as \( W + 9.525 \text{ kg} \), after losing 21 lbs, his current weight is \( W \).
Next, we can set up the calculation for oxygen consumption. The rate of oxygen consumption at his VO2 max is given in mL O2/kg/min. This means:
\[ \text{Oxygen consumption (mL/min)} = \text{VO2 max (mL O2/kg/min)} \times \text{weight (kg)} \]
So, if we calculate the oxygen consumption in one minute at his VO2 max:
\[ \text{Oxygen consumption (mL/min)} = 64.5 , \text{mL O2/kg/min} \times W \]
To find the total oxygen consumption in one hour (which is 60 minutes), we multiply by 60:
\[ \text{Total oxygen consumption (mL in 1 hr)} = 64.5 , \text{mL O2/kg/min} \times W \times 60 \] \[ \text{Total oxygen consumption (mL in 1 hr)} = 3870 , \text{mL O2/kg/hr} \times W \]
To obtain a specific numerical answer, we would need his final body mass \( W \). If you have that information, you can substitute it in to calculate the total mL of oxygen he would consume in one hour.
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