If this man lost 18 lbs

Question

, exercised, and increased his VO2max
to 64.8 mL
O2/kg
body mass/min, how many mL
of oxygen would he consume in 1 hr
?

Answer 1

To calculate the amount of oxygen this man would consume in 1 hour, we first need to determine his new oxygen consumption rate in mL O2/kg body mass/min.

Given that his initial VO2max was 50 mL O2/kg body mass/min and he increased it to 64.8 mL O2/kg body mass/min, we can calculate the change in his oxygen consumption rate:

Change in VO2max = 64.8 mL O2/kg body mass/min - 50 mL O2/kg body mass/min = 14.8 mL O2/kg body mass/min

Next, we need to calculate his body mass after losing 18 lbs. Let's assume that his initial body mass was 160 lbs.

Body mass after weight loss = 160 lbs - 18 lbs = 142 lbs

Now we can calculate his new oxygen consumption rate:

New VO2max = 64.8 mL O2/kg body mass/min

Now, let's calculate the oxygen consumption in 1 hour:

Oxygen consumption in 1 hour = New VO2max * Body mass after weight loss * 60 minutes
Oxygen consumption in 1 hour = 64.8 mL O2/kg body mass/min * (142 lbs / 2.2 lbs/kg) * 60 minutes

Convert pounds to kilograms:
142 lbs / 2.2 lbs/kg = 64.55 kg

Now, let's substitute this value in our formula:

Oxygen consumption in 1 hour = 64.8 mL O2/kg body mass/min * 64.55 kg * 60 minutes
Oxygen consumption in 1 hour = 251208 mL

Therefore, this man would consume 251,208 mL of oxygen in 1 hour after losing 18 lbs, exercising, and increasing his VO2max to 64.8 mL O2/kg body mass/min.