To solve the quadratic equation \((x + 3)^2 = 36\) using square roots, we can follow these steps:
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Take the square root of both sides: \[ x + 3 = \pm 6 \]
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Solve for \(x\) in each case:
- Case 1: \(x + 3 = 6\) \[ x = 6 - 3 = 3 \]
- Case 2: \(x + 3 = -6\) \[ x = -6 - 3 = -9 \]
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Final solutions: \[ x = 3 \quad \text{or} \quad x = -9 \]
So, the solutions to the equation \((x + 3)^2 = 36\) are \(x = 3\) and \(x = -9\).