find the values of a,b, and c for the quadratic equation below (remember ax^2 + bx + c = 0)

Question

x^2 - 7x = 4

Answer 1

To put the equation \( x^2 - 7x = 4 \) in the standard quadratic form \( ax^2 + bx + c = 0 \), we need to rearrange it.

Starting with the given equation:

\[ x^2 - 7x - 4 = 0 \]

Now, comparing this with the standard form \( ax^2 + bx + c = 0 \):

• \( a = 1 \) (coefficient of \( x^2 \))
• \( b = -7 \) (coefficient of \( x \))
• \( c = -4 \) (constant term)

So the values are:

• \( a = 1 \)
• \( b = -7 \)
• \( c = -4 \)