Find the values of a, b, and c for the quadratic equation below (remember

ax2+bx+c=0)


x2−7x=4

1 answer

To rewrite the equation in the standard form of a quadratic equation, \( ax^2 + bx + c = 0 \), we start with the given equation:

\[ x^2 - 7x = 4 \]

We can move 4 to the left side of the equation:

\[ x^2 - 7x - 4 = 0 \]

Now, we can identify the values of \( a \), \( b \), and \( c \):

  • \( a = 1 \) (the coefficient of \( x^2 \))
  • \( b = -7 \) (the coefficient of \( x \))
  • \( c = -4 \) (the constant term)

Thus, the values are:

  • \( a = 1 \)
  • \( b = -7 \)
  • \( c = -4 \)