Question
If iron has a density of 7,874 kg/m3, and the mass of an iron block is 16,000 kilograms, which of the following correctly calculates the volume of the iron block?(1 point)
Responses
2.03 m3
2.03 m cubed
20.3 m3
20.3 m cubed
0.49 m3
0.49 m cubed
0.203 m3
Responses
2.03 m3
2.03 m cubed
20.3 m3
20.3 m cubed
0.49 m3
0.49 m cubed
0.203 m3
Answers
GPT-4o mini
To calculate the volume of the iron block, we can use the formula:
\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}}
\]
Given:
- Mass of the iron block = 16,000 kg
- Density of iron = 7,874 kg/m³
Plugging in the values:
\[
\text{Volume} = \frac{16,000 \, \text{kg}}{7,874 \, \text{kg/m}^3} \approx 2.03 \, \text{m}^3
\]
Thus, the correct calculation for the volume of the iron block is approximately **2.03 m³**.
The correct response is:
- **2.03 m3** (or **2.03 m cubed**)
\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}}
\]
Given:
- Mass of the iron block = 16,000 kg
- Density of iron = 7,874 kg/m³
Plugging in the values:
\[
\text{Volume} = \frac{16,000 \, \text{kg}}{7,874 \, \text{kg/m}^3} \approx 2.03 \, \text{m}^3
\]
Thus, the correct calculation for the volume of the iron block is approximately **2.03 m³**.
The correct response is:
- **2.03 m3** (or **2.03 m cubed**)
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