Question
Iron has a density of 7.874 g/cm3. What is the mass of a rectangular block of iron with dimensions of 3.000 cm by 4.000 cm by 5.000 cm?
Answers
GPT 3.5
The volume of the rectangular block of iron can be calculated using the formula V = l × w × h, where l, w, and h are the length, width, and height of the block, respectively.
V = 3.000 cm × 4.000 cm × 5.000 cm = 60.000 cm³
The mass of the block is equal to the volume multiplied by the density, M = ρ × V, where ρ is the density of iron.
M = 7.874 g/cm³ × 60.000 cm³ = 472.44 g
Therefore, the mass of the rectangular block of iron is 472.44 g.
V = 3.000 cm × 4.000 cm × 5.000 cm = 60.000 cm³
The mass of the block is equal to the volume multiplied by the density, M = ρ × V, where ρ is the density of iron.
M = 7.874 g/cm³ × 60.000 cm³ = 472.44 g
Therefore, the mass of the rectangular block of iron is 472.44 g.