Asked by Jackie

What is the polar form of (3^1/2 - i)?

I know
r=(x^2+y^2)^1/2

and

theta = arctan (y/x)

I know r=2, but how do you find theta?

Answered by Anonymous
¡ò_0^(1/2)¢Æ1/(1+4t©÷) dx
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