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What is the polar form of 1+sina+icosa
9 years ago

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Steve
sina = cos(π/2-a)
cosa = sin(π/2-a)

1+sina+icosa
= 1+cos(π/2-a) + i sin(π/2-a)
= 1 + cis(π/2-a)

There is no simple cis(x) form because of that pesky 1.
9 years ago
Anonymous
Yyh
7 years ago

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