Asked by John

A group of 9 workers make up a business team. One of the 9 is the manager, another member is the engineer. The remaining 7 are analysts. If the entire team is standing in line at the cafeteria on lunch, and the manager is standing 1st in line, and the engineer is standing 2nd, how many different orders can the line be in with the 7 analysts behind them?
Answered by Fred
Use factorials I think.
Answered by PsyDAG
7! = 7 factorial = 7 * 6 * 5 * 4 * 3 * 2 * 1
Answered by John
That's what I was thinking, but do the 2 locked positions screw with my answer?
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