Asked by Tracy
A group of 9 workers decides to send a delegation of 3 to their supervisor to dicusss their grievences.
c.) If there are 4 women and 5 men in the group, how many delegations would include at least 1 women?
I know I have to use combination C(9,1)x C(9,4) but I'm lost after that? Please help?
c.) If there are 4 women and 5 men in the group, how many delegations would include at least 1 women?
I know I have to use combination C(9,1)x C(9,4) but I'm lost after that? Please help?
Answers
Answered by
Patrice
There are 9 of them so a delegation of 3 can go in 9C3 = 84 ways. There are 5 men in them so "all men" delgations will be 5C3= 10.
hence 84-10 = 74 delegations will contain at least one lady.
So what you have done and heard, both are wrong.
Answered by
Tyler
The number of possible delegations without considering any restriction is C(9,3) = 84.
The number of possible delegations which do not include any woman is C(5,3) = 10.
So the answer should be: 84-10 = 74.
I don't know how you get 129, and why is the answer 112. If you write your solution, I could check it to find the flaw (or maybe my solution is flawed).
The number of possible delegations which do not include any woman is C(5,3) = 10.
So the answer should be: 84-10 = 74.
I don't know how you get 129, and why is the answer 112. If you write your solution, I could check it to find the flaw (or maybe my solution is flawed).
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