QuestionA gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6×105 gallons. What is the approximate weight of the water in an Olympic-sized swimming pool? Write the answer in scientific notation.(1 point)Responses5.478×106lb.5.478 times 10 superscript 6 baseline lb.54.78×105lb.54.78 times 10 superscript 5 baseline lb.54.78×106 lb.54.78 times 10 superscript 6 baseline lb.5.478×105lb.5.478 times 10 superscript 5 baseline lb.

To find the approximate weight of the water in an Olympic-sized swimming pool, we can multiply the number of gallons by the weight of one gallon of water.

The pool holds \( 6.6 \times 10^5 \) gallons, and each gallon weighs about 8.3 pounds.

Now we calculate the total weight:

\[
\text{Total Weight} = 6.6 \times 10^5 \, \text{gallons} \times 8.3 \, \text{lb/gallon}
\]

Now we can perform the multiplication:

\[
6.6 \times 8.3 = 54.78
\]

Next, we multiply the powers of ten:

\[
10^5
\]

Putting it all together, we get:

\[
\text{Total Weight} = 54.78 \times 10^5 \, \text{lb}
\]

To write this in proper scientific notation, we can convert \( 54.78 \) into \( 5.478 \) and increase the power of ten by 1:

\[
54.78 \times 10^5 = 5.478 \times 10^6
\]

So, the approximate weight of the water in an Olympic-sized swimming pool is:

\[
\boxed{5.478 \times 10^6 \, \text{lb}}
\]