Question
Three charges of 5 x 10^(-6) C are placed on the vertices of an equilateral triangle of 10cm. Calculate force on each charge.
Answers
bobpursley
Add the two forces as Vectors. You can use arguments of symmetry to simplify it.
F=kQQ/s^2 * 2 cos30, the direction is along the vertex bisector.
F=kQQ/s^2 * 2 cos30, the direction is along the vertex bisector.
Related Questions
Three point charges + q, -q and + q are placed at the vertices P, Q and R of an equilateral triangle...
Three charges sit on the vertices of an equilateral triangle, the side of which are 30.0 cm long. If...
charges of +2uc,+3uc,and -8uc are placed at the vertices of an equilateral triangle of side 10cm.
c...