Asked by help me
Two charges, Q1 and Q2, are held a fixed distance apart. Q1 is exactly twice Q2. You do an experiment: Part a) you double Q1 and measure the force between the charges. Part b) You return Q1 to the original charge, but double Q2 and measure the force between the two charges. How would the force measured in Part a) compare to the force measured in Part b)?
1. The force measured in Part a) would be the same as the force measured in Part b).
2. The force measured in Part a) would be greater than the force measured in Part b).
3. The force measured in Part a) would be smaller than the force measured in Part b).
4. There is no way to tell how the forces in Part a) and Part b) compare since the original force between Q1 and Q2 was never measured.
1. The force measured in Part a) would be the same as the force measured in Part b).
2. The force measured in Part a) would be greater than the force measured in Part b).
3. The force measured in Part a) would be smaller than the force measured in Part b).
4. There is no way to tell how the forces in Part a) and Part b) compare since the original force between Q1 and Q2 was never measured.
Answers
Answered by
Damon
k Q1 Q2 / d^2
2Q1 Q2 = k Q1 2Q2
2Q1 Q2 = k Q1 2Q2
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