Asked by PJ
Does adding 7+2 and then dividing by 2 help you find the find midpoint of line segment JK¯¯¯¯¯¯¯¯ ?
(1 point)
Responses
Yes because (7+2)÷2 calculates the average, or midpoint, of the x-coordinates of points J and K.
Yes because open paren 7 plus 2 close paren divided by 2 calculates the average, or midpoint, of the x -coordinates of points J and K.
No because 7 should be added to 3, then multiplied by 2 to find the midpoint.
No because 7 should be added to 3, then multiplied by 2 to find the midpoint.
Yes because (7+2)÷2 calculates the average, or midpoint, of the y-coordinates of points J and K.
Yes because open paren 7 plus 2 close paren divided by 2 calculates the average, or midpoint, of the y -coordinates of points J and K.
No because (7,2) is not the coordinate of point J or K.
(1 point)
Responses
Yes because (7+2)÷2 calculates the average, or midpoint, of the x-coordinates of points J and K.
Yes because open paren 7 plus 2 close paren divided by 2 calculates the average, or midpoint, of the x -coordinates of points J and K.
No because 7 should be added to 3, then multiplied by 2 to find the midpoint.
No because 7 should be added to 3, then multiplied by 2 to find the midpoint.
Yes because (7+2)÷2 calculates the average, or midpoint, of the y-coordinates of points J and K.
Yes because open paren 7 plus 2 close paren divided by 2 calculates the average, or midpoint, of the y -coordinates of points J and K.
No because (7,2) is not the coordinate of point J or K.
Answers
Answered by
GPT-4o mini
To determine if adding \(7 + 2\) and then dividing by \(2\) helps find the midpoint of line segment \(JK\), we need to consider what \(7\) and \(2\) represent.
If \(7\) and \(2\) are the \(x\)-coordinates of points \(J\) and \(K\), then the calculation \((7 + 2) \div 2\) finds the average of these \(x\)-coordinates, which gives the \(x\)-coordinate of the midpoint.
Similarly, if \(7\) and \(2\) are the \(y\)-coordinates of points \(J\) and \(K\), the calculation can be used to find the \(y\)-coordinate of the midpoint.
Given the responses provided, the best answer that matches this reasoning is:
**Yes because (7+2)÷2 calculates the average, or midpoint, of the x-coordinates of points J and K.**
If \(7\) and \(2\) represent the \(x\)-coordinates, this correctly describes the use of the average to find the midpoint.
If \(7\) and \(2\) are the \(x\)-coordinates of points \(J\) and \(K\), then the calculation \((7 + 2) \div 2\) finds the average of these \(x\)-coordinates, which gives the \(x\)-coordinate of the midpoint.
Similarly, if \(7\) and \(2\) are the \(y\)-coordinates of points \(J\) and \(K\), the calculation can be used to find the \(y\)-coordinate of the midpoint.
Given the responses provided, the best answer that matches this reasoning is:
**Yes because (7+2)÷2 calculates the average, or midpoint, of the x-coordinates of points J and K.**
If \(7\) and \(2\) represent the \(x\)-coordinates, this correctly describes the use of the average to find the midpoint.