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Original Question
Classify each triangle as acute, right or obtuse. 10, 49.5, 50.5 (1 point) These side lengths form a(n) triangle.Question
Classify each triangle as acute, right or obtuse
9.6, 18, 20.1
(1 point)
These side lengths form a(n)
triangle.
9.6, 18, 20.1
(1 point)
These side lengths form a(n)
triangle.
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Answered by
GPT-4o mini
To classify the triangle based on its side lengths, we can use the Pythagorean theorem. For a triangle with sides \(a\), \(b\), and \(c\) (where \(c\) is the longest side), we can determine the type of triangle as follows:
1. If \(a^2 + b^2 > c^2\), it is an acute triangle.
2. If \(a^2 + b^2 = c^2\), it is a right triangle.
3. If \(a^2 + b^2 < c^2\), it is an obtuse triangle.
Given the sides \(9.6\), \(18\), and \(20.1\), we identify \(20.1\) as the longest side, so we have:
- \(a = 9.6\)
- \(b = 18\)
- \(c = 20.1\)
Now, we calculate \(a^2 + b^2\) and compare it to \(c^2\).
1. Calculate \(a^2\):
\[
9.6^2 = 92.16
\]
2. Calculate \(b^2\):
\[
18^2 = 324
\]
3. Calculate \(c^2\):
\[
20.1^2 = 404.01
\]
Now, add \(a^2\) and \(b^2\) together:
\[
a^2 + b^2 = 92.16 + 324 = 416.16
\]
Now we compare \(a^2 + b^2\) to \(c^2\):
\[
416.16 > 404.01
\]
Since \(a^2 + b^2 > c^2\), the triangle is classified as an **acute triangle**.
Thus, these side lengths form an **acute** triangle.
1. If \(a^2 + b^2 > c^2\), it is an acute triangle.
2. If \(a^2 + b^2 = c^2\), it is a right triangle.
3. If \(a^2 + b^2 < c^2\), it is an obtuse triangle.
Given the sides \(9.6\), \(18\), and \(20.1\), we identify \(20.1\) as the longest side, so we have:
- \(a = 9.6\)
- \(b = 18\)
- \(c = 20.1\)
Now, we calculate \(a^2 + b^2\) and compare it to \(c^2\).
1. Calculate \(a^2\):
\[
9.6^2 = 92.16
\]
2. Calculate \(b^2\):
\[
18^2 = 324
\]
3. Calculate \(c^2\):
\[
20.1^2 = 404.01
\]
Now, add \(a^2\) and \(b^2\) together:
\[
a^2 + b^2 = 92.16 + 324 = 416.16
\]
Now we compare \(a^2 + b^2\) to \(c^2\):
\[
416.16 > 404.01
\]
Since \(a^2 + b^2 > c^2\), the triangle is classified as an **acute triangle**.
Thus, these side lengths form an **acute** triangle.
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