Question
classify each triangle as acute, right or obtuse.
10, 49.5, 50.5
these sides form a ____ triangle
10, 49.5, 50.5
these sides form a ____ triangle
Answers
Answer
u sure
Answered by
GPT-4o mini
To classify the triangle formed by sides of lengths 10, 49.5, and 50.5, we can first use the triangle inequality to determine if these lengths can form a triangle. The triangle inequality states that the sum of the lengths of any two sides must be greater than the length of the third side.
Let's check the inequalities:
1. \(10 + 49.5 > 50.5\)
- \(59.5 > 50.5\) (True)
2. \(10 + 50.5 > 49.5\)
- \(60.5 > 49.5\) (True)
3. \(49.5 + 50.5 > 10\)
- \(100 > 10\) (True)
Since all three conditions are satisfied, these sides do form a triangle.
Next, to determine if the triangle is acute, right, or obtuse, we can use the lengths to verify:
1. Find the square of each side:
- \(a = 10\) → \(a^2 = 100\)
- \(b = 49.5\) → \(b^2 = 2450.25\)
- \(c = 50.5\) → \(c^2 = 2550.25\)
2. Check the relationship between \(c^2\) and \(a^2 + b^2\):
- \(a^2 + b^2 = 100 + 2450.25 = 2550.25\)
- \(c^2 = 2550.25\)
Since \(c^2 = a^2 + b^2\), this means the triangle is a **right triangle**.
Thus, the sides 10, 49.5, and 50.5 form a **right triangle**.
Let's check the inequalities:
1. \(10 + 49.5 > 50.5\)
- \(59.5 > 50.5\) (True)
2. \(10 + 50.5 > 49.5\)
- \(60.5 > 49.5\) (True)
3. \(49.5 + 50.5 > 10\)
- \(100 > 10\) (True)
Since all three conditions are satisfied, these sides do form a triangle.
Next, to determine if the triangle is acute, right, or obtuse, we can use the lengths to verify:
1. Find the square of each side:
- \(a = 10\) → \(a^2 = 100\)
- \(b = 49.5\) → \(b^2 = 2450.25\)
- \(c = 50.5\) → \(c^2 = 2550.25\)
2. Check the relationship between \(c^2\) and \(a^2 + b^2\):
- \(a^2 + b^2 = 100 + 2450.25 = 2550.25\)
- \(c^2 = 2550.25\)
Since \(c^2 = a^2 + b^2\), this means the triangle is a **right triangle**.
Thus, the sides 10, 49.5, and 50.5 form a **right triangle**.
Answered by
GPT-4o mini
Let's verify the calculations step by step to ensure accuracy.
Given sides: \(a = 10\), \(b = 49.5\), and \(c = 50.5\).
### Step 1: Check if these can form a triangle
Using the triangle inequality:
1. \(10 + 49.5 > 50.5\) → \(59.5 > 50.5\) (True)
2. \(10 + 50.5 > 49.5\) → \(60.5 > 49.5\) (True)
3. \(49.5 + 50.5 > 10\) → \(100 > 10\) (True)
All inequalities are satisfied, so these can form a triangle.
### Step 2: Determine the type of triangle
We will compare \(c^2\) (where \(c\) is the longest side) with \(a^2 + b^2\).
- **Calculate \(a^2\):**
\[
a^2 = 10^2 = 100
\]
- **Calculate \(b^2\):**
\[
b^2 = 49.5^2 = 2450.25
\]
- **Calculate \(c^2\):**
\[
c^2 = 50.5^2 = 2550.25
\]
### Step 3: Compare \(c^2\) with \(a^2 + b^2\)
- Calculate \(a^2 + b^2\):
\[
a^2 + b^2 = 100 + 2450.25 = 2550.25
\]
Now compare:
- \(c^2 = 2550.25\)
- \(a^2 + b^2 = 2550.25\)
Since \(c^2 = a^2 + b^2\), the triangle is classified as a **right triangle**.
### Conclusion
The analysis is correct; the sides 10, 49.5, and 50.5 do indeed form a **right triangle**. Thank you for prompting the re-check!
Given sides: \(a = 10\), \(b = 49.5\), and \(c = 50.5\).
### Step 1: Check if these can form a triangle
Using the triangle inequality:
1. \(10 + 49.5 > 50.5\) → \(59.5 > 50.5\) (True)
2. \(10 + 50.5 > 49.5\) → \(60.5 > 49.5\) (True)
3. \(49.5 + 50.5 > 10\) → \(100 > 10\) (True)
All inequalities are satisfied, so these can form a triangle.
### Step 2: Determine the type of triangle
We will compare \(c^2\) (where \(c\) is the longest side) with \(a^2 + b^2\).
- **Calculate \(a^2\):**
\[
a^2 = 10^2 = 100
\]
- **Calculate \(b^2\):**
\[
b^2 = 49.5^2 = 2450.25
\]
- **Calculate \(c^2\):**
\[
c^2 = 50.5^2 = 2550.25
\]
### Step 3: Compare \(c^2\) with \(a^2 + b^2\)
- Calculate \(a^2 + b^2\):
\[
a^2 + b^2 = 100 + 2450.25 = 2550.25
\]
Now compare:
- \(c^2 = 2550.25\)
- \(a^2 + b^2 = 2550.25\)
Since \(c^2 = a^2 + b^2\), the triangle is classified as a **right triangle**.
### Conclusion
The analysis is correct; the sides 10, 49.5, and 50.5 do indeed form a **right triangle**. Thank you for prompting the re-check!
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