Rectangle ABDC undergoes a translation vector of <3, -2> in the coordinate plane to produce A'B'D'C'. What will be the coordinates of A' after Jarvis completes this translation A = (-5, 4)?

Answer 1

To find the new coordinates of point A' after the translation vector <3, -2> is applied to point A, we need to perform the following steps:

1. Identify the coordinates of point A:
   $A=(-5,4)$

2. Apply the translation vector <3, -2>:
   We add the x-component of the vector to the x-coordinate of point A, and the y-component of the vector to the y-coordinate of point A.

   • New x-coordinate: $$-5+3=-2$$

   • New y-coordinate: $$4-2=2$$

3. Combine the new coordinates:
   So, the coordinates of A' will be: $A^{\prime }=(-2,2)$.

Therefore, the coordinates of A' after the translation are $(-2,2)$.