Rectangle ABDC undergoes a translation vector of <3, -2> in the coordinate plane to produce A'B'D'C'. What will be the coordinates of A' after Jarvis completes this translation?

A=(-5,4) B=(-1,4) C=(-5,1) D=(-1,1)
A' (_,_)

1 answer

To find the new coordinates of point A after the translation, we will add the translation vector \(\langle 3, -2 \rangle\) to the coordinates of point A.

Point A has coordinates \((-5, 4)\).

Now, we apply the translation:

  • \(x\)-coordinate: \(-5 + 3 = -2\)
  • \(y\)-coordinate: \(4 - 2 = 2\)

Thus, after the translation, the coordinates of point A' will be:

\[ A' = (-2, 2) \]

So the coordinates of A' are \((-2, 2)\).