If rectangle ABDC (coordinates; A(-5, 4), B(-1, 4), C(-5, 1), D(-1, 1) ) is translated horizontally −1 and vertically +3, which of the following correctly depicts rectangle A′B′D′C′ ?

1 answer

To translate the rectangle \( ABDC \) horizontally \( -1 \) (to the left) and vertically \( +3 \) (upwards), we need to apply the translation to each point of the rectangle.

The translation can be represented as:

  • New x-coordinate = Original x-coordinate - 1
  • New y-coordinate = Original y-coordinate + 3

Now, let's apply this translation to each vertex:

  1. Point A:

    • Original coordinates: \( A(-5, 4) \)
    • Translated coordinates: \( A'(-5 - 1, 4 + 3) = A'(-6, 7) \)
  2. Point B:

    • Original coordinates: \( B(-1, 4) \)
    • Translated coordinates: \( B'(-1 - 1, 4 + 3) = B'(-2, 7) \)
  3. Point D:

    • Original coordinates: \( D(-1, 1) \)
    • Translated coordinates: \( D'(-1 - 1, 1 + 3) = D'(-2, 4) \)
  4. Point C:

    • Original coordinates: \( C(-5, 1) \)
    • Translated coordinates: \( C'(-5 - 1, 1 + 3) = C'(-6, 4) \)

Therefore, the new coordinates for the vertices of rectangle \( A'B'D'C' \) after the translation are:

  • \( A'(-6, 7) \)
  • \( B'(-2, 7) \)
  • \( C'(-6, 4) \)
  • \( D'(-2, 4) \)

So the rectangle \( A'B'D'C' \) will have its vertices at these new coordinates.