For which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides?(1 point)

Responses

8(x − 6) = 48
8 left parenthesis x minus 6 right parenthesis equals 48

6(x + 8) = 48
6 left parenthesis x plus 8 right parenthesis equals 48

6x − 8 = 48
6 x minus 8 equals 48

6(x − 8) = 48
6 left parenthesis x minus 8 right parenthesis equals 48

1 answer

To determine which equation allows for the order of steps to first divide both sides by 6 and then to add 8 to both sides, let's analyze the given equations one by one.

  1. 8(x − 6) = 48:

    • Dividing by 6 is not applicable here because 8 is on the left side, not 6.
  2. 6(x + 8) = 48:

    • If you divide both sides by 6, you get (x + 8) = 8. Adding anything to both sides would not yield a meaningful result that involves the variable x in a way that allows for a defined answer by solely using addition following division.
  3. 6x − 8 = 48:

    • In this equation, if you first divide both sides by 6, you would not be able to directly add 8 afterwards since it doesn't fit the equation structure.
  4. 6(x − 8) = 48:

    • If you divide both sides by 6, you get (x − 8) = 8. If you then add 8 to both sides, it would give you x = 16. This sequence is possible.

Thus, the correct answer to the question is:

6(x − 8) = 48.