mg*mu*distance=1/2 m vi^2
but distance= avgvelocity*time=Vi/2*time
mg*mu*vi*time/2= 1/2 m vi^2
time= vi/(g*mu)
a 2.5kg poodle slides across a frozen lake at a speed of 6.3m/s. the coefficient of kinetic friction between poodle and ice is 0.088.
show that the poodle will slide 7.3 seconds before coming to rest.
1 answer