Question
What does a typical persuasive speech begin with? (1 point)
• a set of facts that are meant to support the claim
• a counterclaim with facts that undermines the speech's premise
• something to catch the audience's attention
• an unpopular claim that the speaker supports
• a set of facts that are meant to support the claim
• a counterclaim with facts that undermines the speech's premise
• something to catch the audience's attention
• an unpopular claim that the speaker supports
Answers
GPT-4o mini
A typical persuasive speech begins with **something to catch the audience's attention**.
what is the frequency of a 7.9 * 10^-13 m wave
Formula:
Work:
Answer:
Formula:
Work:
Answer:
GPT-4o mini
To find the frequency of a wave, you can use the formula that relates the speed of light (c), wavelength (λ), and frequency (f):
\[
c = f \times \lambda
\]
Where:
- \( c \) (the speed of light) is approximately \( 3.0 \times 10^8 \) m/s.
- \( \lambda \) is the wavelength in meters.
- \( f \) is the frequency in hertz (Hz).
Given:
- Wavelength \( \lambda = 7.9 \times 10^{-13} \) m.
Rearranging the formula to solve for frequency \( f \):
\[
f = \frac{c}{\lambda}
\]
Now plug in the values:
\[
f = \frac{3.0 \times 10^8 \text{ m/s}}{7.9 \times 10^{-13} \text{ m}}
\]
Calculating:
\[
f = \frac{3.0 \times 10^8}{7.9 \times 10^{-13}}
\]
\[
f \approx 3.7975 \times 10^{21} \text{ Hz}
\]
**Answer:** The frequency of the 7.9 × 10^-13 m wave is approximately \( 3.8 \times 10^{21} \) Hz.
\[
c = f \times \lambda
\]
Where:
- \( c \) (the speed of light) is approximately \( 3.0 \times 10^8 \) m/s.
- \( \lambda \) is the wavelength in meters.
- \( f \) is the frequency in hertz (Hz).
Given:
- Wavelength \( \lambda = 7.9 \times 10^{-13} \) m.
Rearranging the formula to solve for frequency \( f \):
\[
f = \frac{c}{\lambda}
\]
Now plug in the values:
\[
f = \frac{3.0 \times 10^8 \text{ m/s}}{7.9 \times 10^{-13} \text{ m}}
\]
Calculating:
\[
f = \frac{3.0 \times 10^8}{7.9 \times 10^{-13}}
\]
\[
f \approx 3.7975 \times 10^{21} \text{ Hz}
\]
**Answer:** The frequency of the 7.9 × 10^-13 m wave is approximately \( 3.8 \times 10^{21} \) Hz.