Asked by Jewel

According to the Journal of Irreproducible Results, any obtuse angle is a right angle! Here is
their argument.
Given the obtuse angle x, we make a quadrilateral ABCD with  DAB = x, and  ABC =
90◦, andAD = BC. Say the perpendicular bisector toDC meets the perpendicular bisector to
AB at P. ThenPA = PB andPC = PD. So the trianglesPADandPBC have equal sides
and are congruent. Thus  PAD =  PBC. But PAB is isosceles, hence  PAB =  PBA.
Subtracting, gives x =  PAD−  PAB =  PBC −  PBA = 90◦. This is a preposterous
conclusion – just where is the mistake in the “proof” and why does the argument break down
there?

Answers

Answered by Bear
It is advised to not cheat on the PROMYS application problems. If you are stuck on one then try another one.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions