Question

One molecule if bromine (Br2) and two molecule if potassium chloride (KCI) combine in a reaction. How many atoms are in the products?

Answer 1

To determine the number of atoms in the products of the reaction between bromine (Br₂) and potassium chloride (KCl), we must first consider the reactants and how they combine.

1. The given molecules:
- 1 molecule of bromine (Br₂) contains 2 bromine atoms.
- 2 molecules of potassium chloride (KCl) each contain 1 potassium atom and 1 chlorine atom. So, 2 molecules of KCl contain:
- 2 potassium (K) atoms
- 2 chlorine (Cl) atoms

2. Combining these, we can summarize the total atoms from the reactants:
- From Br₂: 2 Br atoms
- From 2 KCl: 2 K atoms + 2 Cl atoms

3. Now, let's add these up:
- Total Br atoms = 2
- Total K atoms = 2
- Total Cl atoms = 2
- Total = 2 Br + 2 K + 2 Cl = 6 atoms

4. The likely reaction involving these reactants could be:
\[
Br_2 + 2 KCl \rightarrow 2 KBr + Cl_2
\]
In this reaction, potassium bromide (KBr) and chlorine gas (Cl₂) are formed.

5. In the products:
- 2 molecules of KBr contain:
- 2 K atoms
- 2 Br atoms
- 1 molecule of Cl₂ contains:
- 2 Cl atoms

6. Therefore, the total number of atoms in the products is:
- Total K = 2
- Total Br = 2
- Total Cl = 2
- Total = 2 K + 2 Br + 2 Cl = 6 atoms

Thus, there are **6 atoms in the products**.