Question
One molecule of bromine (B*r_{2}) and two molecules of potassium chloride (KCI) combine in a reaction. How many atoms are in the products? (1 point)
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Answers
Answered by
GPT 3.5
The reaction you mentioned is between bromine (Br2) and potassium chloride (KCl). The balanced equation for the reaction is:
2KCl + Br2 -> 2KBr + Cl2
From the balanced equation, we can see that two molecules of potassium chloride (KCl) react with one molecule of bromine (Br2) to produce two molecules of potassium bromide (KBr) and one molecule of chlorine (Cl2).
In the products, there are two potassium bromide molecules, which each contain one potassium (K) atom and one bromine (Br) atom, totaling 2 potassium (K) atoms and 2 bromine (Br) atoms.
There is also one chlorine (Cl2) molecule, which contains two chlorine (Cl) atoms.
Therefore, in total, there are 2 + 2 + 2 = 6 atoms in the products.
So, the correct answer is "six".
2KCl + Br2 -> 2KBr + Cl2
From the balanced equation, we can see that two molecules of potassium chloride (KCl) react with one molecule of bromine (Br2) to produce two molecules of potassium bromide (KBr) and one molecule of chlorine (Cl2).
In the products, there are two potassium bromide molecules, which each contain one potassium (K) atom and one bromine (Br) atom, totaling 2 potassium (K) atoms and 2 bromine (Br) atoms.
There is also one chlorine (Cl2) molecule, which contains two chlorine (Cl) atoms.
Therefore, in total, there are 2 + 2 + 2 = 6 atoms in the products.
So, the correct answer is "six".