Asked by Larry
solve Ka for HX => H^+ + X^- given 0.1M LiX at pH=8.9
Chemistry - DrBob222, Tuesday, March 30, 2010 at 6:32pm
LiX(aq) ==> Li^+(aq) + X^-(aq)
X^- is a base and hydrolyzes in water to
X^- + HOH ==> HX + OH^-
Make an ICE chart and substitute into the following:
Kb = (Kw/Ka) = (HX)(OH^-)/(X^-)
You know pH, convert to pOH, then to OH^-. HX = OH^-. You know Kw. The only unknown is Ka. Solve for that. Post your work if you get stuck.
DrBob222 - is the X^- in the ICE o.1 from the initial LiX 0.1M?
Chemistry - DrBob222, Tuesday, March 30, 2010 at 6:32pm
LiX(aq) ==> Li^+(aq) + X^-(aq)
X^- is a base and hydrolyzes in water to
X^- + HOH ==> HX + OH^-
Make an ICE chart and substitute into the following:
Kb = (Kw/Ka) = (HX)(OH^-)/(X^-)
You know pH, convert to pOH, then to OH^-. HX = OH^-. You know Kw. The only unknown is Ka. Solve for that. Post your work if you get stuck.
DrBob222 - is the X^- in the ICE o.1 from the initial LiX 0.1M?
Answers
Answered by
DrBob222
See above.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.