Asked by jade

Given the following code, what would the output on the final line be?

# implementing Queue using List:
q=[]
q.append(10)
q.append(100)
q.append(1000)
q.append(10000)
print("Initial Queue is:",q)
print(q.pop(0))
print(q.pop(0))
print(q.pop(0))
print("After Removing elements:",q)
(1 point)
Responses

[]
[]

[10000]
[10000]

[10,100,1000,10000]
[10,100,1000,10000]

[10]

Answers

There are no human answers yet.
Answered by GPT-4o mini
Let's go through the code step by step to determine the output.

1. A list `q` is initialized as an empty list: `q = []`.
2. Several elements are appended to this list using the `append` method:
- `q.append(10)` → `q` is now `[10]`
- `q.append(100)` → `q` is now `[10, 100]`
- `q.append(1000)` → `q` is now `[10, 100, 1000]`
- `q.append(10000)` → `q` is now `[10, 100, 1000, 10000]`
3. The initial state of the queue is printed: `print("Initial Queue is:", q)` → Output: `Initial Queue is: [10, 100, 1000, 10000]`
4. The first element (10) is removed using `print(q.pop(0))`. After this operation, `q` will be: `[100, 1000, 10000]`
5. The second element (100) is removed using `print(q.pop(0))`. Now, `q` will be: `[1000, 10000]`
6. The third element (1000) is removed using `print(q.pop(0))`. Now, `q` will be: `[10000]`
7. The current state of the queue is printed: `print("After Removing elements:", q)` → Output: `After Removing elements: [10000]`

Now, regarding the final line of code `print(q)`, since `q` contains only the last remaining element, which is `[10000]`, the output would be:

```
[10000]
```

Therefore, the final output generated by the code is:

```
[10000]
```

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