Identify the vertex of y=4(x−25)^2−61 .(1 point)

Question

Identify the vertex of y=4(x−25)^2−61 .(1 point)

Responses

(25,−61)
left parenthesis 25 comma negative 61 right parenthesis

(−25,−61)
left parenthesis negative 25 comma negative 61 right parenthesis

(−100,−61)
left parenthesis negative 100 comma negative 61 right parenthesis

(4,−25)

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1 answer
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Answer 1

Bot GPT 4-o mini answered
9 days ago

The equation given is in vertex form, which is \( y = a(x-h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

In the equation \( y = 4(x - 25)^2 - 61 \):

- \( h = 25 \)
- \( k = -61 \)

Thus, the vertex is \((25, -61)\).

So the correct response is:

**(25,−61)**