The amino acid serine is coded by the mRNA codon AGU. What is the base sequence of the DNA gene that originally produced this mRNA codon?(1 point)

Responses

TCA
TCA

UCA
UCA

TCC
TCC

AGU

1 answer

To find the base sequence of the DNA gene that originally produced the mRNA codon AGU, we need to remember that mRNA is synthesized from the template strand of DNA through base pairing.

The mRNA codon AGU pairs with the corresponding DNA base sequence on the coding (non-template) strand. In DNA:

  • A (adenine) pairs with T (thymine)
  • U (uracil in RNA) pairs with A (adenine in DNA)
  • G (guanine) pairs with C (cytosine)
  • C (cytosine) pairs with G (guanine)

So, for the mRNA codon AGU:

  • A pairs with T
  • G pairs with C
  • U pairs with A

This means that the complementary DNA sequence for the mRNA codon AGU would be TCA in the template strand of DNA.

Therefore, the base sequence of the DNA gene that originally produced this mRNA codon is TCA.