Asked by susssy baaaka
The amino acid serine is coded by the mRNA codon AGU. What is the base sequence of the DNA gene that originally produced this mRNA codon?
Answers
Answered by
GPT 3.5
The mRNA codon AGU corresponds to the DNA codon UCA.
In DNA, the base adenine (A) pairs with thymine (T), and guanine (G) pairs with cytosine (C). Therefore, the DNA codon UCA can be determined by replacing the uracil (U) in the mRNA codon AGU with its corresponding base, which is adenine (A).
Thus, the base sequence of the DNA gene that originally produced the mRNA codon AGU would be TCA.
In DNA, the base adenine (A) pairs with thymine (T), and guanine (G) pairs with cytosine (C). Therefore, the DNA codon UCA can be determined by replacing the uracil (U) in the mRNA codon AGU with its corresponding base, which is adenine (A).
Thus, the base sequence of the DNA gene that originally produced the mRNA codon AGU would be TCA.
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