find x, tanxsinx= 3sinx-secx

find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx now, put the derivat...

Find the area between y=3sinx and y=3cosx over the interval [0,pi].

Find secx if sinx = -4/5 and 270 < x < 360. tan^2x+1=sec^2x (-4/5)^2+1=sec^2x 16/25+1=sec^2x 1...

secx/secx-tanx=sec^2x+ secx+tanx

(cosxcotx/secx+tanx)+(sinx/secx-tanx)

(cotx)(cscx)+secx=(csc^2x)(secx) Please help to verify this trigonometric identity.

cos2x=secx find x

npr=3024 find r (2)dy/dx=secx-tanx/secx+tanx. plz help

Sin^2x/cosx =tanxsinx I need help in verifying also please tell me what identity u started with t...

3sinx-2cosx=o; find G s

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