Asked by Max89
Mercury vapour is used in as the dominant species which is excited in a traditional fluorescent light. The first and second excited states of Mercury occur at 254 and 185 nm.
Calculate the energies of each of these transitions?
What equation am i suppose to use to calculate this answer
Calculate the energies of each of these transitions?
What equation am i suppose to use to calculate this answer
Answers
Answered by
drwls
Energy = h c/(wavelength)
h is Planck's constant, which must have been explained in your reading material.
c is the speed of light.
h is Planck's constant, which must have been explained in your reading material.
c is the speed of light.
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