Question

Mercury vapour is used in as the dominant species which is excited in a traditional fluorescent light. The first and second excited states of Mercury occur at 254 and 185 nm.
Calculate the energies of each of these transitions?
What equation am i suppose to use to calculate this answer
drwls
Energy = h c/(wavelength)

h is Planck's constant, which must have been explained in your reading material.

c is the speed of light.