A critical point is an interior point on the domain of a function f(x) where f'(x)=0 or f'(x) is undefined.
The domain of f(x)=x^(-2*ln(x)) is (0,β) because ln(x) cannot take non-positive arguments.
Now, we need to find f'(x) and where f'(x)=0 or undefined.
If we take the logarithm on both sides and use implicit differentiation, we can find f'(x).
Let y=x^(-2ln(x))
ln(y)=-2ln(x)*ln(x)
ln(y)=-2(ln(x))Β²
differentiate with respect to x
(1/y)*(dy/dx)=-2(2ln(x))(1/x)
(dy/dx)=-4y ln(x)/x
f'(x)=-4x^(-2ln(x)) ln(x)/x
We see immediately that f'(x)=0 when x=1 (i.e. ln(x)=0).
Check to see if f'(x) is undefined at any point in the domain of f(x), and any other points where f'(x) = 0.
Check my work.
Find the critical numbers of the function.
f(x) = x^-2ln(x)
1 answer