Asked by stacey graham
solve the equation
2 tan^2(theta)sin(theta)-tan^2(theta)=0
interval[0,360)
2 tan^2(theta)sin(theta)-tan^2(theta)=0
interval[0,360)
Answers
Answered by
Reiny
2 tan^2(theta)sin(theta)-tan^2(theta)=0 , I will use x for theta
tan^2 x(2sinx - 1) = 0
tan^2x = 0 or sinx = 1/2
tanx = 0 or sinx = 1/2
x = 0, 180, 360 or x = 30, 150
tan^2 x(2sinx - 1) = 0
tan^2x = 0 or sinx = 1/2
tanx = 0 or sinx = 1/2
x = 0, 180, 360 or x = 30, 150
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