Question
The mass of the cube is 21g. The volume of the cube was 7cm 3.. What is the
density?
density?
Answers
GPT-4o mini
Density is defined as mass divided by volume. The formula for density (\(d\)) is:
\[
d = \frac{m}{V}
\]
where \(m\) is the mass and \(V\) is the volume.
Given:
- Mass (\(m\)) = 21 g
- Volume (\(V\)) = 7 cm³
Now, plug in the values:
\[
d = \frac{21 \, \text{g}}{7 \, \text{cm}^3} = 3 \, \text{g/cm}^3
\]
Therefore, the density of the cube is \(3 \, \text{g/cm}^3\).
\[
d = \frac{m}{V}
\]
where \(m\) is the mass and \(V\) is the volume.
Given:
- Mass (\(m\)) = 21 g
- Volume (\(V\)) = 7 cm³
Now, plug in the values:
\[
d = \frac{21 \, \text{g}}{7 \, \text{cm}^3} = 3 \, \text{g/cm}^3
\]
Therefore, the density of the cube is \(3 \, \text{g/cm}^3\).
what is the density
GPT-4o mini
The density of the cube, based on the mass of 21 grams and a volume of 7 cm³, is calculated as follows:
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}} = \frac{21 \, \text{g}}{7 \, \text{cm}^3} = 3 \, \text{g/cm}^3
\]
So, the density is \(3 \, \text{g/cm}^3\).
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}} = \frac{21 \, \text{g}}{7 \, \text{cm}^3} = 3 \, \text{g/cm}^3
\]
So, the density is \(3 \, \text{g/cm}^3\).
student was asked to determine the density of an unknown substance. He
measured the mass of the object and determined it to be 165g. He also measured
the side of the cube using a ruler, it measured to be 4cm on all sides. What is the
density of the cube?
measured the mass of the object and determined it to be 165g. He also measured
the side of the cube using a ruler, it measured to be 4cm on all sides. What is the
density of the cube?
GPT-4o mini
To find the density of the cube, we first need to calculate its volume since it is a cube and all sides are equal.
**Volume of a cube** is given by the formula:
\[
V = \text{side}^3
\]
Given that the side length of the cube is 4 cm:
\[
V = 4 \, \text{cm} \times 4 \, \text{cm} \times 4 \, \text{cm} = 64 \, \text{cm}^3
\]
Now, we have the mass of the object, which is 165 g.
Next, we can calculate the density (\(d\)) using the formula:
\[
d = \frac{m}{V}
\]
Substituting the values:
\[
d = \frac{165 \, \text{g}}{64 \, \text{cm}^3} \approx 2.578125 \, \text{g/cm}^3
\]
Rounding to three significant figures, the density of the cube is approximately:
\[
\text{Density} \approx 2.58 \, \text{g/cm}^3
\]
**Volume of a cube** is given by the formula:
\[
V = \text{side}^3
\]
Given that the side length of the cube is 4 cm:
\[
V = 4 \, \text{cm} \times 4 \, \text{cm} \times 4 \, \text{cm} = 64 \, \text{cm}^3
\]
Now, we have the mass of the object, which is 165 g.
Next, we can calculate the density (\(d\)) using the formula:
\[
d = \frac{m}{V}
\]
Substituting the values:
\[
d = \frac{165 \, \text{g}}{64 \, \text{cm}^3} \approx 2.578125 \, \text{g/cm}^3
\]
Rounding to three significant figures, the density of the cube is approximately:
\[
\text{Density} \approx 2.58 \, \text{g/cm}^3
\]
9. Find the mass of a liquid that has a volume of 28ml and a density of 4.5g/ml.9.
GPT-4o mini
To find the mass of a liquid, you can use the formula for density:
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
We can rearrange this formula to solve for mass:
\[
\text{Mass} = \text{Density} \times \text{Volume}
\]
Given:
- Density = \(4.5 \, \text{g/ml}\)
- Volume = \(28 \, \text{ml}\)
Now, substitute the values into the formula:
\[
\text{Mass} = 4.5 \, \text{g/ml} \times 28 \, \text{ml}
\]
\[
\text{Mass} = 126 \, \text{g}
\]
Therefore, the mass of the liquid is **126 grams**.
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
We can rearrange this formula to solve for mass:
\[
\text{Mass} = \text{Density} \times \text{Volume}
\]
Given:
- Density = \(4.5 \, \text{g/ml}\)
- Volume = \(28 \, \text{ml}\)
Now, substitute the values into the formula:
\[
\text{Mass} = 4.5 \, \text{g/ml} \times 28 \, \text{ml}
\]
\[
\text{Mass} = 126 \, \text{g}
\]
Therefore, the mass of the liquid is **126 grams**.
The density of a liquid is 3.5g/ml. Its mass is 45g. Find the volume.
GPT-4o mini
To find the volume of a liquid given its mass and density, you can use the formula for density:
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
Rearranging the formula to solve for volume gives:
\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}}
\]
Given:
- Mass = \(45 \, \text{g}\)
- Density = \(3.5 \, \text{g/ml}\)
Now, substitute the values into the formula:
\[
\text{Volume} = \frac{45 \, \text{g}}{3.5 \, \text{g/ml}}
\]
Calculating this gives:
\[
\text{Volume} = \frac{45}{3.5} \approx 12.857 \, \text{ml}
\]
Rounding to three significant figures, the volume of the liquid is approximately:
\[
\text{Volume} \approx 12.9 \, \text{ml}
\]
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
Rearranging the formula to solve for volume gives:
\[
\text{Volume} = \frac{\text{Mass}}{\text{Density}}
\]
Given:
- Mass = \(45 \, \text{g}\)
- Density = \(3.5 \, \text{g/ml}\)
Now, substitute the values into the formula:
\[
\text{Volume} = \frac{45 \, \text{g}}{3.5 \, \text{g/ml}}
\]
Calculating this gives:
\[
\text{Volume} = \frac{45}{3.5} \approx 12.857 \, \text{ml}
\]
Rounding to three significant figures, the volume of the liquid is approximately:
\[
\text{Volume} \approx 12.9 \, \text{ml}
\]
620 grams 7000 cm 3 what is the density
GPT-4o mini
To find the density of a substance given its mass and volume, you can use the formula:
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
Given:
- Mass = 620 grams
- Volume = 7000 cm³
Now, substitute the values into the formula:
\[
\text{Density} = \frac{620 \, \text{g}}{7000 \, \text{cm}^3}
\]
Calculating this gives:
\[
\text{Density} = \frac{620}{7000} \approx 0.08857 \, \text{g/cm}^3
\]
Rounding to four significant figures, the density is approximately:
\[
\text{Density} \approx 0.0886 \, \text{g/cm}^3
\]
\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]
Given:
- Mass = 620 grams
- Volume = 7000 cm³
Now, substitute the values into the formula:
\[
\text{Density} = \frac{620 \, \text{g}}{7000 \, \text{cm}^3}
\]
Calculating this gives:
\[
\text{Density} = \frac{620}{7000} \approx 0.08857 \, \text{g/cm}^3
\]
Rounding to four significant figures, the density is approximately:
\[
\text{Density} \approx 0.0886 \, \text{g/cm}^3
\]