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A cube of mass m1 = 7.7 kg is sitting on top of another cube of the same size and mass m2 = 0.6 kg while they are both in free-fall. Ignoring any air resistance, what is the magnitude of the normal force with which the bottom cube is acting on the top cube?

for this question. I used FN=mg. I multiplied 7.7 x9.8 to get 75N but I got it wrong.
Please help
11 years ago

Answers

Anonymous
They are equal to each other so zero force
8 years ago

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