Question

A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)
Responses

1,280−30h=0
1,280 minus 30 h equals 0

30h=10
30 h equals 10

10−30h=0
10 minus 30 h equals 0

1,280+30h=0

Answer 1

To determine how long the water in the cooler will last, we need to set up an equation based on the total amount of water in ounces (1,280 ounces) and the rate at which water is consumed (30 ounces per hour).

We want to express the total ounces of water minus the ounces consumed over time (h hours) set to zero (when the water is all consumed). The correct equation would be:

\[ 1,280 - 30h = 0 \]

This equation states that starting with 1,280 ounces of water and subtracting 30 ounces for each hour (h) will reach zero ounces at some time.

So, the correct response is:

**1,280 - 30h = 0**