What is the irrational square root 28−−√ simplified?(1 point)

To simplify \(\sqrt{28}\):

1. First, factor 28 into its prime factors:
\[
28 = 4 \times 7
\]

2. Now, apply the property of square roots:
\[
\sqrt{28} = \sqrt{4 \times 7} = \sqrt{4} \times \sqrt{7}
\]

3. We know that \(\sqrt{4} = 2\), so:
\[
\sqrt{28} = 2 \times \sqrt{7}
\]

Thus, the simplified form of \(\sqrt{28}\) is:
\[
2\sqrt{7}
\]

This matches the response "2 start root 7 end root".