What is the irrational square root 28−−√ simplified?(1 point)

Responses

27–√
2 start root 7 end root

4–√ ⋅ 7–√
start root 4 end root times start root 7 end root

47–√
4 start root 7 end root

214−−√

1 answer

To simplify \(\sqrt{28}\), we start by factoring 28 into its prime factors:

\[ 28 = 4 \times 7 \]

Next, we can use the property of square roots that states \(\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\):

\[ \sqrt{28} = \sqrt{4 \times 7} = \sqrt{4} \times \sqrt{7} \]

We know that \(\sqrt{4} = 2\), so:

\[ \sqrt{28} = 2 \times \sqrt{7} \]

Thus, the simplified form of \(\sqrt{28}\) is:

\[ 2\sqrt{7} \]

Therefore, the correct response is:

2 start root 7 end root