Question
Draw a sketch of this question ; the angle of elevation of x from y is 30degree. If |xy|=40m how high is x above the level of y
Answers
GPT-4o mini
To sketch this scenario, follow these steps:
1. **Draw a horizontal line** to represent the level of point Y. Label this line as the ground level.
2. **Place point Y** on the left side of the horizontal line. This is the point from which the angle of elevation is measured.
3. **From point Y**, draw a line at an angle of 30 degrees above the horizontal line towards point X. This line represents the line of sight from Y to X.
4. **Mark the point X** somewhere above the horizontal line along the line of sight from Y.
5. **Draw a vertical line** from point X down to the horizontal line (ground level), and label this line as the height (h) from Y to X.
6. **Label the distance |XY|** as 40 meters along the line of sight (the hypotenuse of the triangle formed by Y, X, and the point directly below X on the ground).
Now, to find the height of X above the level of Y, you can use trigonometry. Specifically, you can use the sine function:
\[
\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}
\]
For this problem:
- \(\theta = 30^\circ\)
- The opposite side (height) is what we want to find, let's call it \(h\).
- The hypotenuse |XY| is 40 m.
Using the sine function:
\[
\sin(30^\circ) = \frac{h}{40}
\]
Since \(\sin(30^\circ) = \frac{1}{2}\):
\[
\frac{1}{2} = \frac{h}{40}
\]
Now, solving for \(h\):
\[
h = 40 \times \frac{1}{2} = 20 m
\]
Thus, point X is 20 meters above the level of point Y.
You can visualize this setup by imagining a right triangle where:
- The angle at Y is 30 degrees,
- The hypotenuse (|XY|) is 40 m,
- The vertical height (h) from Y to X is 20 m.
1. **Draw a horizontal line** to represent the level of point Y. Label this line as the ground level.
2. **Place point Y** on the left side of the horizontal line. This is the point from which the angle of elevation is measured.
3. **From point Y**, draw a line at an angle of 30 degrees above the horizontal line towards point X. This line represents the line of sight from Y to X.
4. **Mark the point X** somewhere above the horizontal line along the line of sight from Y.
5. **Draw a vertical line** from point X down to the horizontal line (ground level), and label this line as the height (h) from Y to X.
6. **Label the distance |XY|** as 40 meters along the line of sight (the hypotenuse of the triangle formed by Y, X, and the point directly below X on the ground).
Now, to find the height of X above the level of Y, you can use trigonometry. Specifically, you can use the sine function:
\[
\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}
\]
For this problem:
- \(\theta = 30^\circ\)
- The opposite side (height) is what we want to find, let's call it \(h\).
- The hypotenuse |XY| is 40 m.
Using the sine function:
\[
\sin(30^\circ) = \frac{h}{40}
\]
Since \(\sin(30^\circ) = \frac{1}{2}\):
\[
\frac{1}{2} = \frac{h}{40}
\]
Now, solving for \(h\):
\[
h = 40 \times \frac{1}{2} = 20 m
\]
Thus, point X is 20 meters above the level of point Y.
You can visualize this setup by imagining a right triangle where:
- The angle at Y is 30 degrees,
- The hypotenuse (|XY|) is 40 m,
- The vertical height (h) from Y to X is 20 m.
Related Questions
When an airplane leaves the runway, its angle of elevation is 18 and its speed is 275 feet per seco...
Sketch a diagram on the question, a boy 1.4m tall, stood 10m away from a tree of height 12m, calcu...
A boat is heading towards a lighthouse, whose beacon-light is 136 feet above the water. From point A...
A boat is heading towards a lighthouse, whose beacon-light is 111 feet above the water. From point A...