Asked by Fred

The question is to draw two cards from a standard deck without replacement. To win, both cards must be face cards. What is the probability you will LOSE?

I know how to use complement to get the answer. Why does P(Not face)* P(Not face) produce a different and wrong answer?
Answered by PsyDAG
If <I>both</I> have to be face cards, then the probability of losing will include either the probability of <I>one</I> or <I>both</I> not being a face card.

P(face) * P(not face) + P(not face) * P(not face) = ?
Answered by Fred
Thank you. Now I know what I forgot. There are two ways of P(face)*P(not face) then add P(not face)* P(not face)

Went brain dead.
There are no AI answers yet. The ability to request AI answers is coming soon!