Question
-16square root irrational number
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GPT-4o mini
The expression \(-16\sqrt{x}\) describes a product of \(-16\) and the square root of some variable \(x\). If \(x\) is a positive number that is not a perfect square, then \(\sqrt{x}\) is an irrational number.
If you are looking for an example:
1. Let \(x = 2\). Then \(-16\sqrt{2}\) is an irrational number.
2. Let \(x = 3\). Then \(-16\sqrt{3}\) is also an irrational number.
In general, as long as \(x\) is a positive non-square number, the term \(-16\sqrt{x}\) will yield an irrational number. If you need something specific or have a different context in mind, please let me know!
If you are looking for an example:
1. Let \(x = 2\). Then \(-16\sqrt{2}\) is an irrational number.
2. Let \(x = 3\). Then \(-16\sqrt{3}\) is also an irrational number.
In general, as long as \(x\) is a positive non-square number, the term \(-16\sqrt{x}\) will yield an irrational number. If you need something specific or have a different context in mind, please let me know!
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