Let's break down each of the expressions to find the total number of atoms for each compound.
### 1. **For \(2\text{MgCl}_2\):**
- **Mg:**
- There are 2 molecules, each contains 1 Mg atom:
- \(2 \text{Mg} = 2 \times 1 = 2 \text{ Mg atoms}\)
- **Cl:**
- Each molecule contains 2 Cl atoms:
- \(2 \text{MgCl}_2 = 2 \times 2 = 4 \text{ Cl atoms}\)
- **Total Atoms:**
- Total = \(2 \text{ (Mg)} + 4 \text{ (Cl)} = 6 \text{ total atoms}\)
### Summary for \(2\text{MgCl}_2\):
- Mg: **2**
- Cl: **4**
- Total Atoms: **6**
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### 2. **For \(\text{NaBr}\):**
- **Na:**
- There is 1 Na atom:
- \(1 \text{Na} = 1 \text{ Na atom}\)
- **Br:**
- There is 1 Br atom:
- \(1 \text{Br} = 1 \text{ Br atom}\)
- **Total Atoms:**
- Total = \(1 \text{ (Na)} + 1 \text{ (Br)} = 2 \text{ total atoms}\)
### Summary for \(\text{NaBr}\):
- Na: **1**
- Br: **1**
- Total Atoms: **2**
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### 3. **For \(4\text{H}_2\text{O}\):**
- **H:**
- Each H₂O molecule contains 2 H atoms:
- \(4 \text{H}_2\text{O} = 4 \times 2 = 8 \text{ H atoms}\)
- **O:**
- Each H₂O molecule contains 1 O atom:
- \(4 \text{H}_2\text{O} = 4 \times 1 = 4 \text{ O atoms}\)
- **Total Atoms:**
- Total = \(8 \text{ (H)} + 4 \text{ (O)} = 12 \text{ total atoms}\)
### Summary for \(4\text{H}_2\text{O}\):
- H: **8**
- O: **4**
- Total Atoms: **12**
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### Total Masses (As Previously Calculated):
- Mass of \(\text{MgCl}_2\): **94 amu**
- Mass of \(\text{NaBr}\): **103 amu**
- Mass of \(\text{H}_2\text{O}\): **18 amu**
### Final Summary:
- \(2\text{MgCl}_2\):
- Mg: **2**,
- Cl: **4**,
- Total Atoms: **6**
- \(\text{NaBr}\):
- Na: **1**,
- Br: **1**,
- Total Atoms: **2**
- \(4\text{H}_2\text{O}\):
- H: **8**,
- O: **4**,
- Total Atoms: **12**
- Mass of \(\text{MgCl}_2\): **94 amu**
- Mass of \(\text{NaBr}\): **103 amu**
- Mass of \(\text{H}_2\text{O}\): **18 amu**