Iron chloride and water react according to the equation shown the table shows the atomic masses of the elements involved in the reaction. What is the total mass of the actant in the table? We have FE for element mass of an Adam is 56 next is CI massive at 35 next is H massive Adam is One next Element zero mass of an atom is 16 so what the answer be 161 AMU 179 AMU 21 5 AM you are 108 AMu

To calculate the total mass of the reactants in the given reaction involving iron chloride (FeCl₃) and water (H₂O), we first need to identify the molecular formulas and the corresponding atomic masses from the data you've provided.

1. **Iron chloride (FeCl₃)**
- Iron (Fe): 1 atom × 56 amu = 56 amu
- Chlorine (Cl): 3 atoms × 35 amu = 105 amu
- Total mass of FeCl₃ = 56 amu + 105 amu = 161 amu

2. **Water (H₂O)**
- Hydrogen (H): 2 atoms × 1 amu = 2 amu
- Oxygen (O): 1 atom × 16 amu = 16 amu
- Total mass of H₂O = 2 amu + 16 amu = 18 amu

Now, to find the total mass of the reactants (FeCl₃ + H₂O), we add the two total masses together:

\[
\text{Total mass of reactants} = \text{mass of FeCl₃} + \text{mass of H₂O}
\]
\[
\text{Total mass of reactants} = 161 \text{ amu} + 18 \text{ amu} = 179 \text{ amu}
\]

So, the total mass of the reactants is **179 amu**.