Asked by Jenny
Determine Kc at 298 K for the reaction 2 CH4(g) reverse reaction arrow C2H2(g) + 3 H2(g), given the following data at 298 K. (Hint: How are Kc and Kp for the reaction related?)
CH4(g) + H2O(g) reverse reaction arrow CO(g) + 3 H2(g) Kp = 1.2 multiplied by 10-25
2 C2H2(g) + 3 O2(g) reverse reaction arrow 4 CO(g) + 2 H2O(g) Kp = 1.1 multiplied by 102
H2(g) + 1/2 O2(g) reverse reaction arrow H2O(g) Kp = 1.1 multiplied by 1040
CH4(g) + H2O(g) reverse reaction arrow CO(g) + 3 H2(g) Kp = 1.2 multiplied by 10-25
2 C2H2(g) + 3 O2(g) reverse reaction arrow 4 CO(g) + 2 H2O(g) Kp = 1.1 multiplied by 102
H2(g) + 1/2 O2(g) reverse reaction arrow H2O(g) Kp = 1.1 multiplied by 1040
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